The present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice the age of the son. Find the present age of the father.
Answer: Option B Solution: Let the son’s present age be x years. Then, father’s present age = (3x + 3) years
==> (3x + 3 + 3) = 2 (x + 3) + 10 ==> 3x + 6 = 2x + 16 ==> x = 10.
hence, father’s present age = (3x + 3) = ((3 x 10) + 3) Years = 33 Years.
Incorrect
Answer: Option B Solution: Let the son’s present age be x years. Then, father’s present age = (3x + 3) years
==> (3x + 3 + 3) = 2 (x + 3) + 10 ==> 3x + 6 = 2x + 16 ==> x = 10.
hence, father’s present age = (3x + 3) = ((3 x 10) + 3) Years = 33 Years.
Question 2 of 15
2. Question
1 points
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Raman’s salary was decreased by 50% and subsequently increased by 50%. How much percent (%) does he lose?
Answer: Option A Solution: Let the original salary = Rs. 100
New final salary = Rs. 150 of (50% of Rs.100)
==> Rs.((150/100)*(50/100)*100) = Rs.75
Decrease = 25%
Incorrect
Answer: Option A Solution: Let the original salary = Rs. 100
New final salary = Rs. 150 of (50% of Rs.100)
==> Rs.((150/100)*(50/100)*100) = Rs.75
Decrease = 25%
Question 3 of 15
3. Question
1 points
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A bag contains 50 Ps, 25 Ps and 10 Ps coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.
Answer: Option C Solution: Let the number of 50 Ps, 25 Ps and 10 Ps coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10) ==> 206 ==> 50x + 45x + 8x = 4120 ==> 1o3x = 4120 ==> x=40.
Number of 50 Ps. coins = (5 x 40) = 200
Number of 25 Ps. coins = (9 x 40) = 360
Number of 10 Ps. coins = (4 x 40) = 160
Incorrect
Answer: Option C Solution: Let the number of 50 Ps, 25 Ps and 10 Ps coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10) ==> 206 ==> 50x + 45x + 8x = 4120 ==> 1o3x = 4120 ==> x=40.
Number of 50 Ps. coins = (5 x 40) = 200
Number of 25 Ps. coins = (9 x 40) = 360
Number of 10 Ps. coins = (4 x 40) = 160
Question 4 of 15
4. Question
1 points
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Worker a takes 8 hours to do a job. Worker b takes 10 hours to do the same job. How long should it take both a and b, working together but independently, to do the same job?
Answer: Option D Solution: a’s 1 hour’s work = 1/8 b’s 1 hour’s work = 1/10
(a + b)’s 1 hour’s work = (1/8) +(1/10)=9/40
Both a and b will finish the work in 40/9 days.
Incorrect
Answer: Option D Solution: a’s 1 hour’s work = 1/8 b’s 1 hour’s work = 1/10
(a + b)’s 1 hour’s work = (1/8) +(1/10)=9/40
Both a and b will finish the work in 40/9 days.
Question 5 of 15
5. Question
1 points
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A train 100 m long is running at the speed of 30 km/hr. Find the time taken by it to pass a man standing near the railway line.
Answer: Option C Solution: Speed of the train = (30 x 5/18) m/ sec ==> (25/3) m/sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100/(25/3) = (100 *(3/25)) sec = 12 sec
Incorrect
Answer: Option C Solution: Speed of the train = (30 x 5/18) m/ sec ==> (25/3) m/sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100/(25/3) = (100 *(3/25)) sec = 12 sec
Question 6 of 15
6. Question
1 points
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A man takes 3 hours 45 minutes to row a boat 15 km downstream of a river and 2 hours 30 minutes to cover a distance of 5 km upstream. Find the speed of the river current in km/hr.
Answer: Option A Solution: Given word contains 8 different letters. When the vowels aue are always together, we may suppose them to form an entity, treated as one letter.
Then, the letters to be arranged are dgntr (aue).
Then 6 letters to be arranged in 6p6 = 6! = 720 ways.
The vowels in the group (aue) may be arranged in 3! = 6 ways.
Required number of words = (720×6) = 4320.
Incorrect
Answer: Option A Solution: Given word contains 8 different letters. When the vowels aue are always together, we may suppose them to form an entity, treated as one letter.
Then, the letters to be arranged are dgntr (aue).
Then 6 letters to be arranged in 6p6 = 6! = 720 ways.
The vowels in the group (aue) may be arranged in 3! = 6 ways.
Required number of words = (720×6) = 4320.
Question 10 of 15
10. Question
1 points
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In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3 men and 2 ladies?
Answer: Option D Solution: (3 men out 6) and (2 ladies out of 5) are to be chosen.
Required number of ways = (6c3x5c2) = [6x5x4/3x2x1] x [5×4/2×1] = 200.
Incorrect
Answer: Option D Solution: (3 men out 6) and (2 ladies out of 5) are to be chosen.
Required number of ways = (6c3x5c2) = [6x5x4/3x2x1] x [5×4/2×1] = 200.
Answer: Option B Solution: Let the average after 17th inning = x.
Then, average after 16th inning = (x – 3).
==> 16 (x – 3) + 87 = 17x or x = (87 – 48) = 39.
Incorrect
Answer: Option B Solution: Let the average after 17th inning = x.
Then, average after 16th inning = (x – 3).
==> 16 (x – 3) + 87 = 17x or x = (87 – 48) = 39.
Question 14 of 15
14. Question
1 points
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If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?
Answer: Option D Solution:
Let the required weight be x kg. Less weight, Less cost (Direct Proportion)
∴ 250 : 200 :: 60 : x ==> 250x x = (200 x 60)
==> x = (200 x 60)/250 x = 48 paise
Incorrect
Answer: Option D Solution:
Let the required weight be x kg. Less weight, Less cost (Direct Proportion)
∴ 250 : 200 :: 60 : x ==> 250x x = (200 x 60)
==> x = (200 x 60)/250 x = 48 paise
Question 15 of 15
15. Question
1 points
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The ratio between the speeds of two trains is 7: 8. If the second train runs 440 kms in 4 hours, then the speed of the first train is:
Answer: Option A Solution: Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = (440/4) = 110
x = (110/8) = 13.75
Hence, speed of first train = (7 x 13.75) km/hr = 96.25 km/hr
Incorrect
Answer: Option A Solution: Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = (440/4) = 110
x = (110/8) = 13.75
Hence, speed of first train = (7 x 13.75) km/hr = 96.25 km/hr